Mth100 gdb Sollution

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Mth100 gdb solution Part a

Number of ways vehs can be grouped together

(3x Jeeps& 1 car) or (2x jeeps and 2 x cars) or (1x jeep and 3 x cars) or 4 cars

=(6C3×4C1)+(6C2×4C2)+(6C1×4C3)+(4C4)= 195 part b

=10P6−9P5

=15200−15120=136080

136080, (6 Digit password can be formed if the password cannot start with 0 and no digit appears more than one.)

Part b =10P6−9P5

=151200−15120=136080